Which shows the four-term polynomial and factored form of x2 6x â€"" 27? x2 3x â€"" 9x â€"" 27 = (x 3)(x â€"" 9) x2 6x â€"" 3xâ€"" 27 = (x 6)(x â€"" 3) x2 9x â€"" 3x â€"" 27 = (x 9)(x â€"" 3) x2 3x â€"" 6x â€"" 27 = (x 3)(x â€"" 6).

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step-by-step explanation:

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation:

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step-by-step explanation: