In a competition with USA, Canada, England and Mexico, how many different ways can the countries place first, second and third? a 3
b 24
c 4
d 9

B

Step-by-step explanation:

There are 4 countries. If a country places first, it cannot place 2nd or 3rd or fourth. That leaves 3 that can. So this uses the counting principle

4 countries could be first

3 countries could be second

2 countries could be 3rd

1 country can be last.

4*3 * 2 * 1 = 24 different ways.

hi,

6x times 4 is 24x and 5 times 4 is 20, so the answer is 24x+20.

hope this and for a little humor i am groot.

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

eventually after a few more steps, your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x