Given that E is the midpoint of AD and BC, which of the following proves that AB∥CD?
HELP ASAP!

O is the midpoint of BC.

Step-by-step explanation:

(i) From the figure, △AOB and △DOC

We know that AB∥CD and ∠BAO and ∠CDO are alternate angles

So we get

∠BAO=∠CDO

From the figure, we also know that O is the midpoint of the line AD

We can write it as AO=DO

According to the figure we know that ∠AOB and ∠DOC are vertically opposite angles.

So we get ∠AOB=∠DOC

Therefore, by ASA congruence criterion we get

△AOB≅△DOC.

(ii) We know that △AOB≅△DOC

So we can write it as

BO=CO(c.p.c.t)

Therefore, it is proved that O is the midpoint of BC.

yes   because as the functions are graphed they eventually will intersect unless otherwise

step-by-step explanation: