If the probability that the Islanders will beat the Rangers in a game is 5/6, what is the probability that the Islanders will win at most two out of five games in a series against the Rangers? Round your answer to the nearest thousandth.

The chance that the Islanders will win n games out of 6 is:

0.47 ^ n + (1 - 0.47) ^ (6 - n) * 6! / n! / (6 - n!)

So, the chance of winning 4 games is 0.205605

the chance of winning 5 games is 0.072932

the chance of winning all 6 games is 0.010779

Adding these together we get 0.289316

Rounding to the nearest thousandth we get 0.289 (or 28.9%)

alright well the answers to your question is

2xy/9 hope this have a nice day : )

step-by-step explanation: