Write an equation to match each situation a. → Mary had a debt of $30. She earned $15 more now she has .
b.→ A diver was at the depth of 10ft . Then he sank 5ft. then he sank 15ft more . now he is at depth of ft.
c.→ The temperature was 2*c and feel 7* . Then it rose 4*. Now the Temperature is *c.

-15$

30 ft

6*c

I hope this helps

Step-by-step explanation:

a. → Mary had a debt of $30. She earned $15 more now she has _x = $30 + $15.

b.→ A diver was at the depth of 10ft . Then he sank 5ft. then he sank 15ft more . now he is at depth of _x = 10 + 5 + 15 ft.

c.→ The temperature was 2*c and feel 7* . Then it rose 4*. Now the Temperature is _x = 2 + 4 *c.

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92