Select Is a Function or Is not a Function to correctly classify each relation. Is a Function Is not a Function
{(2, 2),(4, 4),(6, 6),(8, 8)}
Is a Function – { ( 2, 2 ),( 4, 4 ),( 6, 6 ),( 8, 8 ) }
Is not a Function – { ( 2, 2 ),( 4, 4 ),( 6, 6 ),( 8, 8 ) }
{(0, 3),(3, 5),(5, 6),(8, 4)}
Is a Function – { ( 0, 3 ),( 3, 5 ),( 5, 6 ),( 8, 4 ) }
Is not a Function – { ( 0, 3 ),( 3, 5 ),( 5, 6 ),( 8, 4 ) }
{(1, 2),(3, 3),(4, 8),(6, 3)}
Is a Function – { ( 1, 2 ),( 3, 3 ),( 4, 8 ),( 6, 3 ) }
Is not a Function – { ( 1, 2 ),( 3, 3 ),( 4, 8 ),( 6, 3 ) }
{(3, 4),(5, 2),(5, 6),(7, 3)}
Is a Function – { ( 3, 4 ),( 5, 2 ),( 5, 6 ),( 7, 3 ) }
Is not a Function – { ( 3, 4 ),( 5, 2 ),( 5, 6 ),( 7, 3 ) }

1. Yes, is a function {(2, 2),(4, 4),(6, 6),(8, 8)}

2. Yes, is a function {(0, 3),(3, 5),(5, 6),(8, 4)}

3. Yes, is a function {(1, 2),(3, 3),(4, 8),(6, 3)}

4. No, not a function {(3, 4),(5, 2),(5, 6),(7, 3)}

Step-by-step explanation:

1. Since there is one value of y for every value of x in  {(2, 2),(4, 4),(6, 6),(8, 8)} , this relation is a function.

2. Since there is one value of y for every value of x in {(0, 3),(3, 5),(5, 6),(8, 4)}, this relation is a function.

3. Since there is one value of y for every value of x in {(1, 2),(3, 3),(4, 8),(6, 3)}, this relation is a function.

4. Since x=5 produces y=2 and y=6, the relation {(3, 4),(5, 2),(5, 6),(7, 3)}, is not a function.

0/5 is 0, 2/0 is undefined, and 0/0 is indeterminate.

step-by-step explanation:

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step-by-step explanation:

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