Substance A has 2% alcohol mixture, and substance B has 6% alcohol mixture. To mix substance A and B for a capacity of 60 liters with 3.2% alcohol mixture, how many liters of substance A and B are used each?

18 liters of 6% substance B

42 liters of 2% substance A

Step-by-step explanation:

let x be the liters of 6%, the balance of 60 - x liters is the 2% together they make 60 liters of 3.2%

6x + 2(60 - x) = 3.2(60)

distribute

6x + 120 - 2x = 192

Combine like terms

4x = 72

Divide bothsides by 4

x = 18 liters of 6%

60 - x = 42 liters of 2%

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step-by-step explanation: