A ship maneuvers to within 2.50×103 m of an island’s 1.76 × 103 m high mountain peak and
fires a projectile at an enemy ship 6.18 × 102
m on the other side of the peak, as illustrated.
The ship shoots the projectile with an initial
velocity of 2.52×102 m/s at an angle of 73.4
◦ velocity of 2.52×102 m/s at an angle of 73.4
◦
.
The acceleration of gravity is 9.81 m/s
2
How close (vertically) does the projectile
come to the peak?
.

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.

you estimate that the angle of elevation to the top of the 86th floor (the observatory) is 82 .the total height of the building is another 123 meters above the 86th floor.

leave feedback if u need : )