A waterfall has a height of 1300 feet. If you have a stern upward from the top of the falls within natural velocity of 16 ft./s. The height of the pebble edge and feet after T seconds is given by the equation H equals -16t^2+16t+1300. how long after the pebble is thrown will it hit the ground?

step-by-step explanation:

5×5×5+2(8)÷2(2)+3(3)

15+16÷4+9

31÷13

do 31÷13 and u will get ur answer

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)