(3^-2 × 4^-2)^-3 = 12^x
In the given expression find the value of x.

Given that (3^-2×4^-2)^-3 = 12^x

⇛ [(3×4)^-2]^-3 = 12^x

Since a^m × b^m = (ab)^m

⇛(12^-2)^-3 = 12^x

⇛ 12^(-2×-3) = 12^x

Since (a^m)^n = a^mn

⇛ 12^6= 12^x

⇛6 = x

Since the bases are equal then exponents must be equal

Therefore,x = 6

Additional comment:-

If the bases are equal then exponents must be equal.

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for the first question it would be the second answer for the second question it would be the third answer and for the third question it would be the first answer

step-by-step explanation:

step-by-step explanation: