Mathematics, 30.11.2021 21:40 destinydiamond6887

Find the equation of the normal to the circle, whose equation is given below, at the point (-4,4). (x + 2)^2 + (y - 3)^2 = 5
Give your answer in the form y = mx + c.

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Find the equation of the normal to the circle, whose equation is given below, at the point (-4,4). (x + 2)^2 + (y - 3)^2 = 5 Give your answer in the form y = mx + c.

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Another question on Mathematics

Find the equation of the normal to the circle, whose equation is given below, at the point (-4,4). (x + 2)^2 + (y - 3)^2 = 5
Give your answer in the form y = mx + c.