Mathematics, 30.11.2021 22:00 tayler1911
An object is launched straight up into the air at an initial velocity of 64 feet per second. It is launched from a height of 6 feet off the ground. Its height H in feet, at t seconds is given by the equation H=-16t^2*64t+6. Find all times t that the object is at a height of 54 feet off the ground.
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An object is launched straight up into the air at an initial velocity of 64 feet per second. It is l...
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