There are two bowls. One of them has 60gems and the other has 40gems. Some of them are red. All the gems from the two bowls are now put into a third bowl. What fraction of the gems in the third bowl will be red?.

hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb

4

step-by-step explanation:

●yes, this statement is absolutely apt.

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