Write an equation of a line that passes through (-1,2) and is parallel to a line with x-intercept (3,0) and y-intercept (0,1)

answer: 7270

step-by-step explanation:

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step-by-step explanation:

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )