What is the equation of line that passes through(-6,-3) and is parrelel to the line 5x-3y=9

y+3=5/3(x+6)

Step-by-step explanation:

Since it is parallel to 5x-3y=9, you need to find the slope of that line because then you would find the slope to your line.

5x-3y=9

5x=9+3y

5x-9=3y

y=5/3x-3, and the slope would be 5/3.

Now you can apply point slope form to get an equation.

y+3=5/3(x+6)

x + 7

Step-by-step explanation:

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

angle addition postulate

2x=56

step-by-step explanation: