Suppose y varies jointly as x and z. What is y when x = 2 and z = 3, if y = 20 when x = 4 and z = 3?

y = 10

Step-by-step explanation:

Given y varies jointly as x and z then the equation relating them is

y = kxz ← k is the constant of variation

To find k use the condition y = 20 when x = 4 and z = 3 , then

20 = k × 4 × 3 = 12k ( divide both sides by 12 )

= k , that is

k =

y = xz ← equation of variation

When x = 2 and z = 3 , then

y = × 2 × 3 = 5 ×  2 = 10

you can first factor out the n to get n(1+5). we know that 1+5 is 6, so we just have 6n.

they disappear if your absent from to long. i found out that the hard way.

step-by-step explanation:

brainliest lol i just need one more brainliest.