You are planning the menu for your restaurant. Each evening you offer two different meals and have at least 240 customers. For Saturday night you plan to offer roast beef and teriyaki chicken. The beef costs you $5 per serving and the chicken costs you $3 per serving. You have a budget of at most $1200 for meat for Saturday night. Write a system of linear inequalities that shows the various numbers of roast beef and teriyaki chicken meals you could make for Saturday night. Let x represent the beef dinners and y represent the chicken dinners.

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )

1/6

step-by-step explanation:

question: match the eqaution with its graph -8x - 5y = 40

answer: 8 x 5 = 40

x= absiss

y= orderly

so you have a proportional graph

question answered by

(jacemorris04)