A kite 100 ft above the ground moves horizontally at a speed of 14 ft/s. At what rate (in rad/s) is the angle (in radians) between the string and the horizontal decreasing when 200 ft of string have been let out? Incorrect: Your answer is incorrect. rad/s

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

c

step-by-step explanation: easy math

d. you cannot tell because there are no values shown.

2, 2, 2 or -4, 20, 29

step-by-step explanation:

there is two ways you can do it.