If cot of theta is the square root of 3, calculate (sin of theta)(cot of theta) - cos^2 of theta (in exact numbers)

\frac{\sqrt{3} }{2}  - .75

Step-by-step explanation:

cot Θ = Sqrt (3)

SinΘ = 1/2                         CscΘ = 2

CosΘ = Sqrt3 /  2              SecΘ = 2Sqrt3 / 3

TanΘ = Sqrt3 / 3               CotΘ = Sqrt (3)

Cotangent is Adjacent over Opposite

Adjacent = Sqrt 3

Opposite = 1

That means the Hyp = 2 (Pythag Theorem)

Sin Θ * Cot Θ - CosΘ ² =

1/2 * Sqrt 3 - .75 = (Sqrt3 / 2) - .75

Sqrt3 / 2 - .75 is as far as I can get.

b

step-by-step explanation:

given

- 2 (3x + 12y - 5 - 17x - 16y + 4 )

simplify the parenthesis by collecting like terms

= - 2 (- 14x - 4y - 1) ← distribute the parenthesis by - 2

= 28x + 8y + 2 → b