Flying against the wind, a jet travels 4060 miles in 7 hours. Flying with the wind the same jet travels 3760 miles in 4 hours. What is the rate of the jet in still air and what is the rate of the wind?

Step-by-step explanation:

let j = jet speed in still air

let w be wind speed

(j - w)7 = 4060

7j - 7w = 4060

7j = 7w + 4060

 j = w + 580

              (j + w)4 = 3760

4(w + 580) + 4w = 3760

4w + 2320 + 4w = 3760

                     8w = 1440

                       w = 180 mi/hr

 j = 180 + 580 = 760 mi/hr    supersonic at most altitudes

the answer is d

step-by-step explanation:

hello :

by applying the distributive property :

6 × 4.3 = 6 × ( 4 + 0.3 )

            =   (6 ×   4) + (6 ×   0.3)

            = 24 + 1.8

6 × 4.3 = 25.8