Given that for all values of x, f(x)=3x+p
g(x)=px+4
and fg(x)=6x+q
where p and q are constants. Work out the value of p and q.

p=3 q=7

Step-by-step explanation:

3x+px=6x

px =6x-3x= 3

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

all you have to do is multiply them both to see how many out comes you can put:

3 x 2 = 6

you can make 6 diferent combinations of crusts and toppings.

~batmans wife dun dun