The Nielsen Company conducts survey each year about the use of various media, such as television. A representative sample of adult Americans was surveyed in 2010, and the mean number of minutes per week spent watching television was 576 minutes and sample standard deviation was 60 minutes. An independently selected representative sample of adults was surveyed in 2011, the mean was 646 minutes and sample standard deviation was 80 minutes. Suppose that sample size in each year was 1000. Estimate the difference in the mean spent watching television in 2010 and the mean time spent in 2011 using a 99% confidence interval. Interpret the interval in context.

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.

i believe it is the square root of 122 because when you turn it on it's side, to where the 5 inches is on the bottom, it looks like it is the same length.