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Mathematics, 07.12.2021 18:50 hedaya
In right triangle ABC, sin B = 2x + 0.42 and cos C = 9x + 0.84. Solve for x.
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Prove (a) cosh2(x) โ sinh2(x) = 1 and (b) 1 โ tanh 2(x) = sech 2(x). solution (a) cosh2(x) โ sinh2(x) = ex + eโx 2 2 โ 2 = e2x + 2 + eโ2x 4 โ = 4 = . (b) we start with the identity proved in part (a): cosh2(x) โ sinh2(x) = 1. if we divide both sides by cosh2(x), we get 1 โ sinh2(x) cosh2(x) = 1 or 1 โ tanh 2(x) = .
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In right triangle ABC, sin B = 2x + 0.42 and cos C = 9x + 0.84. Solve for x....
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