Jace walked a total distance of StartFraction 5 Over 6 EndFraction of a mile to school this week. If he walked the same distance each of the 5 days, how far did he walk each day? One-sixth of a mile
One-fifth of a mile
StartFraction 6 Over 25 EndFraction of a mile
StartFraction 25 Over 6 EndFraction miles

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step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)

add 5 subtract 1

step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet