Identify the first five terms of the sequence in which a1 = 3 and an = 4an−1− 5 for n ≥ 2.

Step-by-step explanation:

a1 = 3

an = 4an-1 - 5

a2 = 4×3 - 5 = 12 - 5 = 7

a3 = 4×7 - 5 = 28 - 5 = 23

a4 = 4×23 - 5 = 92 - 5 = 87

a5 = 4×87 - 5 = 348 - 5 = 343

3, 7, 23, 87, 343

Step-by-step explanation:

Using the recursive rule and a₁ = 3 , then

a₂ = 4a₁ - 5 = 4(3) - 5 = 12 - 5 = 7

a₃ = 4a₂ - 5 = 4(7) - 5 = 28 - 5 = 23

a₄ = 4a₃ - 5 = 4(23) - 5 = 92 - 5 = 87

a₅ = 4a₄ - 5 = 4(87) - 5 = 348 - 5 = 343

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step-by-step explanation:

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the required function is .

step-by-step explanation:

from the given table it is noticed that the graph passing through (-3,7), (0,4), (3,1) and (8,-4).

it is a linear function because the value of y is decrease by one as the value of x increase by 1.

the slope of the function is

the slope of the function is -1 and the y-intercept is 4.

the slope intercept form is

where, m is slope and b is y-intercept.

therefore the required function is . the graph of this function is shown below.