If x = a + b, y = a Omega + b Omega square, z = a Omega square + b Omega show that x + y + z = 0

mrbilldoesmath!

answer: a parabola

steps:

(x-1)(x+4)   = x(x+4) - 1(x+4) = (x^2 + 4x) - (x+4)

                = x^2 +4x -x -4   = x^2 +3x -4

which is a parabola

mrb

differentiate (x^14(x^-2)^4with respect to the variable

the parentheses don't balance in your input.

differentiate 0 with respect to

the final answer is

0

hope this

triangle eg 7.5 × cos "a" or 7.5 × sin "b" or 6 tan"a"