Find the area of parallelogram ABCD given m2 A= 300 and the following measures. х
D
с
30°
A
В
AB= 10 in.; AD = 6 in.
A=
O 30 in.2
O 30V3 in.2
o 60 in.2

=

x=0.8898305 is the answer to that equation

secant-secant formula:

(whole secant) x (external part) =           (whole secant) x (external part)

(8+y-2) *8=                                           (y+4+6) *6

(y+6)*8 = (y+10) *6

distribute

8y+48 = 6y +60

subtract 6y from each side

2y +48 = 60

subtract 48 from each side

2y = 12

divide by 2

y = 6

sv =     (y+4+6)

sv   = 6+4+6

sv = 16