Find the 63rd term of the arithmetic sequence 17, 26, 35

a₆₃ = 575

Step-by-step explanation:

The nth term of an arithmetic sequence is

= a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 17 and d = a₂ - a₁ = 26 - 17 = 9 , then

a₆₃ = 17 + (62 × 9) = 17 + 558 = 575

your answer would be 10x - 1

5x + 5

step-by-step explanation:

you should always add the diagrams and graphs we cannot see. this particular question is kind of borderline because we can make a graph for you.

(f + g)x = -x^2 +3x + 5 + x^2 + 2x

(f + g)x = 5x + 5

the graph of z = 5x + 5 is shown below. always use desmos when in doubt.