Verica didn't solve this radical equation correctly. Here is their work:

Your turn; x+3 = V1 + 2x

X

2x-2 = x-1

(zoa) = (-1)

2x-2=X²+1

0 =X²-2x-3

O=(x-3)(x+1)

x=3 or x=1

.

Why does Verica (correctly) square both sides of the

equation in Step 2?

.

What mistake does Verica make between Step 2 and

Step 3? Fix Verica's work below.

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50

a is the correct

-362

step-by-step explanation:

(12)(4)+2(12)-34(12)+2(12)-3

  \/         \/         \/         \/

  48 +   24 -   408 + 24 - 3

      \   /               \   /

          72     -     432 - 3 = -363

step-by-step explanation:

let

we know that

the y-intercept is the y-coordinate of the point when the value of x is equal to zero

so

the y-coordinate of the point a is the y-intercept

the answer part a) is

the value of y-intercept is

part b) find the slope m

we know that

the value of the slope is equal to

substitute the values

therefore

the answer part b) is

the value of the slope is equal to

the general answer is

the slope is

the value of y-intercept is