A 100,000 kg spacecraft traveling to the left at -0.01 m/s docks with a 400,000 kg spacecraft traveling to the right at 0.02 m/s. If they move together after docking, how fast are they moving?

a)(x-2)^2+(y-1)^2=9

step-by-step explanation:

(picture explains)

2425

step-by-step explanation:

answer: the angel abc is 30°,and the abc is a triangle where the angel bac is 90°

so ac is the half of 24=12ft,and from the pythagorean theorem we find ba

ba=√bc^2-ac^2=√576-144=√432=12√3ft

so bac is 12+12√3=12(1+√3)ft