Find the values of the constant m for which the line y = mx is a tangent to the curve y=2x^2 - 4x + 8

m = 4x - 4.

Step-by-step explanation:

y = 2x^2 - 4x + 8.

To find the slope of the tangent at the point (x, y) we find the derivative.

y' = 4x - 4.

So m = 4x - 4.

-22

times both sides by 2, times () by 8, add alile terms, move terms, add alike and caculate divide both sides by 3

answer: you need to organize this better it does not make sense.

step-by-step explanation: ?