Find the domain of y= 2/3 square root of x+5-4

Set the radicand in
√
x
−
5
x
-
5
greater than or equal to
0
0
to find where the expression is defined.
x
−
5
≥
0
x
-
5
≥
0
Add
5
5
to both sides of the inequality.
x
≥
5
x
≥
5
The domain is all values of
x
x
that make the expression defined.
Interval Notation:
[
5
,
∞
)
[
5
,
∞
)
Set-Builder Notation:
{
x
|
x
≥
5
}
{
x
|
x
≥
5
}
The range of an even indexed radical starts at its starting point
(
5
,
0
)
(
5
,
0
)
and extends to infinity.
Interval Notation:
[
0
,
∞
)
[
0
,
∞
)
Set-Builder Notation:
{
y
|
y
≥
0
}
{
y
|
y
≥
0
}
Determine the domain and range.

Iknow one of the answers is a and maybe b but not 100% sure about b