Point slope form question

How would I turn (2,-5) (-3, 10) into a point slope equation?

y+5=-3(x-2)

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(10-(-5))/(-3-2)

m=(10+5)/-5

m=15/-5

m=-3

y-y1=m(x-x1)

y-(-5)=-3(x-2)

y+5=-3(x-2)

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15