Whomever please Find the perimeter of the triangle that has vertices at the points R(2,1), S (2,5), and T(4,
1). Round the answer to the nearest hundredth (2 decimal places).

A) 35.78
B) 32
C) 21.54
D)10.47

answer: a.

step-by-step explanation: the answer is a. because, you need to converge the fractions to find a solution.

l.jnl.j/n.m,lm,

step-by-step explanation:

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.