A bag contains 5 red marbles, 6 blue, and 4 green. If three marbles are drawn what is the probability to the nearest 10th all three are blue

4.4%

Step-by-step explanation:

Probability of drawing blue first is 6 in 15

Assuming you get that one, the second is 5 in 14 (as you've taken a blue one out)

If that's successful you have 5 in 13 chances of pulling another blue

As you want the first AND second AND third to happen, you multiply them…

(6/15)*(5/14)*(4/13) = 0.04395

So as a percentage, to the nearest tenth is 4.4%

answer: b.

step-by-step explanation:

the y coordinate for point b is 0, and answer b is the only one with that y coordinate.