A gym is 100 feet long and 90 feet wide. On a scale drawing, the gym is 8 inches long. What is the width of the gym?

Let the width be x

Given, Actual length = 100 ft = 1200 inches

Actual width = 90 ft = 1080 inches

We can say that the values are in proportion to each other. So,

Thus, on the scale drawing the width of the gym is 7.2 inches.

Hope this helps :)

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !