A rectangle is 4 in wide and 2 in tall. If it is enlarged to a width of 20 in, then how tall Will it be?

4

Step-by-step explanation:

It will still be 4 in. tall.  Do you mean that the parameter will remain the same?  You need to specify all constraints when asking a question (in other words: give all the details that you are given -- although I know that a lot of instructors are unnecessarily vague).  If the parameter will remain the same value then we can use the rectangle parameter formula to determine the new value for the height (aka. "length" or "how tall"):

Parameter = Length1 + Length2 + Width1 + Width2

 or

P = 2l + 2w

 so...

P = 2(4) + 2(2) = 8 + 4 = 12

 therefore...

1.   12 = 2(x) + 2(4)

2.   12 = 2x + 8

3.   12 - 8 = 2x + 8 - 8

4.   4 = 2x

5.   4 / 2 = x · 2 / 2

6.  2 = x

x = 2 in.

idc

step-by-step explanation:

idk

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!