Does anyone know how to do this? Also can you explain it so I know how to do the rest of it

Explanation:

Locate two corresponding sides where we know their lengths. The only pair we can go for are the 24 and 20 sides for A and B respectively. Both sides are vertical.

Divide the side for B over A's corresponding value to get the scale factor

scale factor = B/A = 20/24 = (5*4)/(6*4) = 5/6

The sides of figure B are 5/6 as long compared to the sides of figure A.

The scale factor 5/6 = 0.83 is smaller than 1, so the jump from figure A to figure B is a reduction (rather than an enlargement).

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

step-by-step explanation:

hans did not square the 40-unit side; he merely multiplied it by 2.   incorrect.