During the first second of a journey a car travels 2m. it travels 4m during the second, 6m during the third and the second and so on. Assuming that the distance continue to 11X rease in a linear sequences(a) find the the distance travelled in the 10th second(b) the total distance travelled up to 10s

the image is given below

since the options are not given so we draw it from the equation

the given equation is

y = (x-1) (x+4)

y = y² + 3x - 4

the above equation is a quadratic equation which will have two roots. if we draw the graph for it, it will look like this

"standard form:

3x2 + 14x − 10 = 0

solutions based on quadratic formula:

x1   = −14 − √ 142 − 4×3×(−10) /   2×3   = −14 − 2 × √ 79 /   6   ≈ −5.296

x2   = −14 + √ 142 − 4×3×(−10) /   2×3   = −14 + 2 × √ 79 /   6   ≈ 0.629

tried on you are knowing that we can't leave the picture in the graph ok no problem now you need to send it in the question group