What is the 100th term of sequence for -25,-13,1,11

The 100th term i 1163

Step-by-step explanation:

From -25 to -13 is a positive jump of 12, and

from -13 to 1 is a positive jump of 14, and

from 1 to 11 is a positive jump of 10

So there's something wrong with the given sequence  Let's assume that the sequence is actually -25, -13, -1, 11.  There's always a positive jump of 12 from one term to the following term.

Regard this as an arithemeti sequence with first term -25 and common difference (d) = 12.

Then the general formula for this sequence is a(n) = a(1) + d(n - 1).  For the given situation, it becomes a(n) = -25 + 12(n - 1), and for a(100) we have

a(100) = -25 + 12(100 - 1), or

a(1000 = -25 + 12(99) = 1163

The 100th term is 1163

let's cover over the formula of the vertex:

y = a(x – h)^2 + k

in this formula, (h,k) are the vertex, always remember that the positive or negative value of the vertex is based on the sign it has.

for example, if the vertex is -3,-6 then both the x and y value would have the positive sign attached to it and if it were a positive x and y value, then a negative sign would be attached to it.

with that being said, for our problem the x value is a positive one so we are looking for a number with a negative sign next to it, in this case the first and second choice.

however, for the first answer choice it isn't quite part of the formula so we know that the answer choice correctly displays the x value.

to confirm, we can see if the -1 fits correctly with the second answer choice, and as mentioned above a negative number will have a positive sign attached to it. so, for our problem we can see that -1 has been changed to +1, so we can confirm that the second answer choice is correct.

hence, our final answer is y=(x - 1)^2 + 1

if you need just tell me and i will come to the rescue.

step-by-step explanation: