[-5,x); set-builder notation

A = {x | -5 ≤ x < x | x in R}

Step-by-step explanation:

Solution set is {-5,-4,-3,-2,-1}

Set-builder notation --> A = {x | -5 ≤ x < x | x in R}

step-by-step explanation:

you divide the denominator by the numerator on both sides and if the quotients are equal then the fractions are equivalent