Ben performed a transformation on trapezoid PQRS to create P′Q′R′S′, as shown in the figure below: A four quadrant coordinate grid is drawn. Trapezoid PQRS with coordinates at P negative 6, negative 3. Q is at negative 4, negative 3. R is at negative 2, negative 5. S is at negative 7, negative 6. Trapezoid P prime Q prime R prime S prime with coordinates are drawn at P prime 3, negative 6. Q prime is at 3, negative 4. R prime is at 5, negative 2. S prime is at 6, negative 7.

What transformation did Ben perform to create P′Q′R′S′?

Group of answer choices

Rotation of 270° counterclockwise about the origin

Reflection across the line of symmetry of the figure

Reflection across the y-axis

Rotation of 90° counterclockwise about the origin

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

set up the composite function and evaluate.

f(2x−x2)=−3x2+6x−1

what? ?

what type of question is thiss

step-by-step explanation:

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!