Log4(x+3)+log4x=1 what is the solution set to this equation

Hello!

I'm currently new to Log, but can help in the best way possible.

We can rewrite this into exponential form:

(x+3) = 4^1 + 4x^1

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If not shown correctly, above, further apologize.

If factored and isolated;

1-xlog(4) = log(256x)

x

≈

0.03710403

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I hope this helps,

-Oceanbreeze24