On a mid-day game show, 20 members of the audience were chosen from the crowd. According to the rules of the game show, one of these contestants will be chosen at random to win a prize, assuming they satisfy a
set of randomly chosen criteria. If 8 people do not meet the criteria, but Andrew does, what is the probability
that Andrew will be chosen to win the prize?

THE ANSWER IS I WOULD SAY B 1/20

Step-by-step explanation:

YOU HAVE 20 CONTESTANTS AND 8 DON'T MEET THE CRITERIA BUT ONE PERSON DOES IT'S 1/20

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer