5) So far you have a MP3 Player with 0.5 GB of music already stored on the MP3 player and know that each song is about 0.002 GB of memory. What are the possible numbers of additional songs that you can put on the MP3 player if it holds at most 2 GB?

Any whole number between 0 and 750, including both endpoints.

One example could be 700 additional songs.

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Explanation:

x = number of additional songs, some nonnegative whole number

1 song takes up 0.002 GB, so x of them take up 0.002x GB of memory.

Add on the 0.5 GB already used to get the expression 0.002x+0.5 to represent the total amount of storage taken up. We want this expression to be 2 or smaller.

This says the most songs we can add are 750.

Because x is the number of songs, it doesn't make sense to have x be negative. This means or is the case as well.

Combining and produces the compound inequality

The number of additional songs is any whole number between 0 and 750, including both endpoints.

The roster notation of this set could look like this: {0, 1, 2, ..., 748,749,750}

The triple dots indicate "keep this pattern going". That way we don't have to fill in all 751 values which would be a tedious process.

So you can add on something like 700 songs because it's between those endpoints mentioned, but cannot add something like 800 songs.

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

the answer is b.

step-by-step explanation: