The sum of three consecutive odd integers is 129. find the integers

Step-by-step explanation:

Let the three consecutive integers be x, x + 2 and x + 4

So, the given condition is:

x + x + 2 + x + 4 = 129

3x + 6 = 129

Subtract 6 to both sides

3x = 129 - 6

3x = 123

Divide 3 to both sides

x = 123/3

x = 41

So, the integers are:

x = 41

x + 2 = 41 + 2 = 43

x + 4 = 41 + 4 = 45

Hope this helped!

Let the first number be = n

The difference of consecutive odd numbers is 2

So,the next two numbers are (n+2)(n+4)

Then,

→ (n) + (n+2) + (n+4) = 129

Remove brackets:

→ n + n + 2 + n + 4 = 129

→ 3n + 6 = 129

→ 3n = 129 – 6

→ 3n = 123

→

So, (n+2) = 41 + 2 = 43 , (n+4) = 41 + 4 = 45

» The three integers are 41, 43 and 45

the answer to the question is a

step-by-step explanation:

it has the same slope and the same y-intercept.

y + 11 = -7/9(x - 18)

y + 11 =-7/9x + 14

b

y = -7/9x + 3

y-intercept (0, 3)

don't know what that says sorry i can't you

step-by-step explanation:

idk what it says