Find the equation of the tangent to the circle, whose equation is given below, at the point (-4,2). (x+2)^2+(y−3)^2=5

The equation of the tangent is y = –2x – 6

The step by step process is in the pic attached.

The top part was cropped out, it says the centre point is (–2,3)

i don't even know man. edge inuity be messing with us. i had to ask a question too.

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so: