PLEASE ANSWER ASAP Please give an answer i can copy paste into the answer box, please nothing extra

Using the following 3 equations, answer the questions:

11x + y = 4x + y = -2x - 2y = 18

How can you determine which equations can be graphed more easily using x- and y-intercepts, rewriting in slope-intercept form, or using a table of values?

Which method works best for you personally? When does it not work as well?

Step-by-step explanation:

I'll assume these are the equations:

11x + y =  18

4x + y  = 18

-2x - 2y = 18

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The easiest approach to graphing, for me, is to rearrange each to y=mx+b (slope-intercept) format:

It seems to me that all three can be graphed easily from simply reading the slope and y-intercept values.  Since these are straight lines, all we need is two points for each line, and one is standing out in plain view, the y-intercept:  (0,y-intercept).  The second point can be determined by using whatever value of x makes the calculation easy

An example:  y =  - x -9.  Plot (0,-9) for the y intercept, and then calculate one additional point (e.g., for x = - 9).  (-9,0)  Then connect a straight line between these two points and presto (metric term for magic), a graph. For the first equation, I picked 20 for x.  For x = 20, y = -29.  That was easy, and we have the second point:  (1,-10)

See the attachment for how this was done.  The first points are all for the y-intercept (0,[18 or 9]).  All of the second points were calculated in my head by using a convenient value for x.

This approach doesn't work well for non-linear equations.  There, I find it easier to set up a table of values - a spreadsheet such as Excel is my tool for the calculations.

The attachment also demonstrates the Really Easy Way to graph functions.  DESMOS, a free, and excellent, online calculator.

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step-by-step explanation:

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option a.

step-by-step explanation:

if you look closely at the graph, we can notice that the function is not defined at two different points.

if you look at functions b and c, you will notice that both functions are not defined at just one point. the function b is not defined at x= -5/2 and function c is not defined at x=-5. both options are discarded, given that our function should not be defined at two fiferent points.

now, if you look closely at the graph you will notice that the function sketched is not defined at x=5 and x=-2.