In the rectangular trapezoid ABCD AC is driven by a CD (see figure). Find the area of the trapezoid if AC = 3, AD = 5.

solution given:

let's see only in a right-angled triangle Δ ACD.

AC=3 units

AD=5 units

since Δ ACD is a right-angled triangle. It satisfies Pythagoras law

25=9+

=25-9=16

Now

Area of rectangle Δ ACD=

similarly,

since AB=CE=2.4 units

Δ ACE is a right-angled triangle. It satisfies Pythagoras law.

now

area of trapezoid=area ofΔACD+Area of ΔABC

=6+

Step-by-step explanation:

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step-by-step explanation:

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see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph