Graph the line y= 2/3x +1

Step-by-step explanation:

Given the linear equation, y = ⅔x + 1, where the slope, m = ⅔, and the y-intercept, (0, 1) where b = 1.

In order to graph the given linear equation, start by plotting the coordinates of the y-intercept, (0, 1). As we know, the y-intercept is the point on the graph where it crosses the y-axis. It coordinates are (0, b), for which the value of b represents the value of the y-intercept in slope-intercept form, y = mx + b.

From the y-intercept, (0, 1), we must use the slope, m =  ⅔ (rise 2, run 3) to plot the other points on the graph. Continue the process until you have sufficient amount of plotted points on the graph that you could connect a line with.

Attached is a screenshot of the graphed linear equestion, which demonstrates how I plotted the other points on the graph using the "rise/run" techniques" discussed in the previous section of this post.    

We are asked to graph the line y=2/3x+1.

2/3 is the slope of this line (Rise/Run)

The rise is how many units we move up; the run is how many units we move left or right.

For this line, 2 is the rise, and 3 is the run.

Now, 1 is the y-intercept. (where the graph touches the y-axis)

First, plot this point: (0,1)

Then, move 2 units up and 3 to the left (Up 2, over 3, up 2, over 3)

When you have a line, take a ruler and connect these points, and you will have the graph of y=2/3x+1.

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

853.3

step-by-step explanation: